Find the H.C.F of 2x square-8,2x+4. Plz fast it’s aurgent
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Answer:
2x²-x-1 = 2x²-2x+1x-1
= 2x(x-1)+1(x-1)
= (x-1)(2x+1)
4x²+8x+3 = 4x²+2x+6x+3
=2x(2x+1)+3(2x+1)
(2x+1)(2x+3)
HCF is (2x+1)
LCM is (x-1)(2x+1)(2x+3)
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