Question

find the h.c.f of 520and 1430

Answer 1

1 x 520 = 520
2 x 260 = 520
4 x 130 = 520
5 x 104 = 520
8 x 65 = 520
10 x 52 = 520
13 x 40 = 520
20 x 26 = 520

Finding Factors of 1430
1 x 1430 = 1430
2 x 715 = 1430
5 x 286 = 1430
10 x 143 = 1430
11 x 130 = 1430
13 x 110 = 1430
22 x 65 = 1430
26 x 55 = 1430

Factors of 520 are [1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520]

Factors of 1430 are [1, 2, 5, 10, 11, 13, 22, 26, 55, 65, 110, 130, 143, 286, 715, 1430]

The common factors of 520 and 1430 are [1, 2, 5, 10, 13, 26, 65, 130]

The largest common factor of 520 and 1430 is 130

HCF is 130

Answer 2

Hey!!!!

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By Prime Factorisation Method,

=> 520 = 2² x 5 x 13

=> 1430 = 2 x 5 x 13 x 11

Thus HCF(520,1430) = 2 x 5 x 13

Thus HCF = 130

Hope this helps