Question

Find the [H+], pH, and pOH if the [OH-] = 1.0x10-7.

Answer 1

Answer:

[H+] = 10^-7

pH = 7

pOH = 7

Explanation:

We know that Kw=[H+][OH-]

Kw = 1 * 10^-14

[H+] = [OH-]

Hence [H+] = [OH-] = 10^-7

Now, pH = -log[H+]

Hence pH = 7 = pOH

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