Find the HCF and LCM of 10224 and 1608 using prime factorization method.
(Class 10 Maths Sample Question Paper)
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Prime factors of 10224 = 2 × 2 × 2 ×2 × 3× 3 × 71= 2⁴ × 3² × 71¹
Prime factors of 1608 = 2×2×2×3 ×67 = 2³ × 3¹ × 67¹
HCF of 10224 and 1608 = 2³ × 3 = 8 ×3 = 24
HCF × LCM = Ist number × 2nd number
24 × LCM = 10224 × 1608
LCM = (10224 × 1608) / 24
LCM = 10224 × 67
LCM = 685008
Hence, the HCF of 10224 & 1608 is 24 & the LCM of 10224 & 1608 is 685008.
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Prime factors of 1608 = 2×2×2×3 ×67 = 2³ × 3¹ × 67¹
HCF of 10224 and 1608 = 2³ × 3 = 8 ×3 = 24
HCF × LCM = Ist number × 2nd number
24 × LCM = 10224 × 1608
LCM = (10224 × 1608) / 24
LCM = 10224 × 67
LCM = 685008
Hence, the HCF of 10224 & 1608 is 24 & the LCM of 10224 & 1608 is 685008.
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