Math, asked by savita31121979, 3 days ago

find the HCF and LCM of 12and16​

Answers

Answered by fahims8080
0

Answer:

Lcm =48 and HCF =4

Step-by-step explanation:

According to the information provided in the question it is given as

Numbers = 12 and 16

We need to find the L C M and H C F

LC M means the lowest common multiple

HC F means the highest common factor

FIRST FACTORS OF BOTH NUMBERS.

12=2\times 2\times 3

16=2\times 2\times 2\times2

 Now taking common factors,

=2\times 2

Remaining factor,

=2\times \times2\times3

Then

multiply all

=2\times2\times2\times2\times3

=48

Hence, LCM of 16 and 12 is 48.

Now  HCF

Find the prime factorization of 12

12 = 2 × 2 × 3

Find the prime factorization of 16

16 = 2 × 2 × 2 × 2

To find the HCF, multiply all the prime factors common in both numbers

Hence

HCF = 2 × 2

HCF = 4

So Lcm =48 and HCF =4

Answered by souhardya51
1

Answer:

Lcm =48 and HCF =4

Step-by-step explanation:

According to the information provided in the question it is given as

Numbers = 12 and 16

We need to find the L C M and H C F

LC M means the lowest common multiple

HC F means the highest common factor

FIRST FACTORS OF BOTH NUMBERS.

12=2\times 2\times 312=2×2×3

16=2\times 2\times 2\times216=2×2×2×2

Now taking common factors,

=2\times 2=2×2

Remaining factor,

=2\times \times2\times3=2××2×3

Then

multiply all

=2\times2\times2\times2\times3=2×2×2×2×3

=48

Hence, LCM of 16 and 12 is 48.

Now HCF

Find the prime factorization of 12

12 = 2 × 2 × 3

Find the prime factorization of 16

16 = 2 × 2 × 2 × 2

To find the HCF, multiply all the prime factors common in both numbers

Hence

HCF = 2 × 2

HCF = 4

So Lcm =48 and HCF =4

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