Question

Find the HCF and LCM of 26 and 91 pairs of integers and verify that LCM × HCF = product


two numbers.​

Answer 1

Answer:

kindly see the answer below...

Step-by-step explanation:

Here,

HCF and LCM of 26 & 91 is

$13 | \frac{26}{2}. \frac{91}{7} |$

so, the HCF is 13 and LCM is 182.

Now, we have to verify that

LCM×HCF = product

$lcm \times hcf$

$= 182 \times 13$

$= 2366$

$= 26 \times 91$

$= product$

thanks a lot...

plz♥..if this is helpful..

Answer 2

$\begin{array}{r | 1} 2 & 26 \\ \cline{2 - 2} 13 & 13 \\ \cline{2-2} & 1 \end{array}$

$\begin{array}{r | 1} 7 & 91 \\ \cline{2 - 2} 13 & 13 \\ \cline{2-2} & 1 \end{array}$

⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━⠀⠀

⠀⠀

☯ Prime Factorization:

• 26 = 2 × 13
• 91 = 7 × 13

LCM: 2 × 7 × 13

LCM = 182

HCF = 13

$\bigstar$ Verification:

$\bf LCM \times HCF = Product \ of \ Both \ numbers\\\\\\:\implies\sf 182 \times 13 = 26 \times 91 \\\\\\:\implies\boxed{\frak{\pink{ 2366 = 2366}}}$

⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀Hence Verified!