Question

Find the HCF and LCM of 270, 405 and 315 USING Fundamental theorem of

Arithmetic.​

Answer 1

Answer:

45

Step-by-step explanation:

01) Prime factorization of 270 =2×3×3×3×5.

02) Prime factorization of 315=3×3×5×7.

03) Prime factorization of 405=3×3×3×3×5.

04) So,HCF(270,315,405)=3×3×5 = 45

Hope this will help you

Answer 2

The given question we have to Find the HCF and LCM of 270, 405 and 315 USING Fundamental theorem of

Arithmetic.

The given numbers are 270,405,315.

The LCM. is Least Common Multiplier.

The HCF stands for Highest Common Divisor.

The prime factorisation of given numbers are

270 is 2*3*3*3*5

315 is 3*3*5*7

405 is 3*3*3*3*5

The LCM for above digits is 3*3*5*2*3*3*7

Therefore the LCM for the given number is 5670.

.The HCF for the given numbers is 3*3*5

.The HCF for the given numbers is 3*3*5Therefore the HCF for the given numbers is 45 .

# spj2

we can find the similar questions through the link

https://brainly.in/question/9669069?referrer=searchResults