Find the HCF and LCM of 404 and 96 and verify that HCFxLCM=Product of two given numbers.
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Q. Find the HCF and LCM of 404 and 96 and verify that HCF×LCM = product of two given numbers.
Solution :
First do the prime factorisation of 404 and 96 ,
96 = 2×2×2×2×2×3 = (2)^5
404 = 2×2×101 = (2)^2
Therefore, HCF of 404 and 96 is (2)^2 = 4
Now,
LCM (404,96) = (404×96)/HCF
= (404×96)/4 = 9696
===================================
Verification :
⭐ HCF×LCM = product of two given numbers.
HCF = 4
LCM = 9696
Product of 96,404 = 96×404 = 38784
Product of HCF and LCM
= 4×9696 = 38784
Hence,
HCF×LCM = product of two given numbers. (verified)
Solution :
First do the prime factorisation of 404 and 96 ,
96 = 2×2×2×2×2×3 = (2)^5
404 = 2×2×101 = (2)^2
Therefore, HCF of 404 and 96 is (2)^2 = 4
Now,
LCM (404,96) = (404×96)/HCF
= (404×96)/4 = 9696
===================================
Verification :
⭐ HCF×LCM = product of two given numbers.
HCF = 4
LCM = 9696
Product of 96,404 = 96×404 = 38784
Product of HCF and LCM
= 4×9696 = 38784
Hence,
HCF×LCM = product of two given numbers. (verified)
imperialdragon1:
Thanks
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