Math, asked by dushyantpaposa, 9 months ago

Find the HCF and LCM of 510 and 92 and verify that HCF × LCM = Product of two given numbers

Answers

Answered by surjasaha
4

Answer:

Sol: HCF of 510 and 92. 510 = 92 x 5 + 50 92 = 50 x 1 + 42 50 = 42 x 1 + 8 42 = 8 x 5 + 2 8 = 2 x 4 + 0 ∴ HCF of 510 and 92 = 2 Product of two numbers = Product of their LCM and HCF 510 x 92 = 2 x LCM LCM = (510 x 92) / 2 = 23460 ∴ LCM of 510 and 92 = 23460.

Step-by-step explanation:

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Answered by Blaezii
10

LCM and HCF is equals to product of two numbers.

Proved.

Step-by-step explanation :

\bigstar\;\boxed{\bf 510} - \begin{array}{r | l}2 & 510}\\\cline{2-2}  3& 225 \\\cline{2-2} 5 & 85 \\\cline{2-2} 17& 17\\ \cline{2-2} & 1\end{array}\\ \\ \\\rule{300}{1.5}\\ \\ \bigstar\;\boxed{\bf 92} - \begin{array}{r | l}2 & 92}\\\cline{2-2}  2& 46 \\\cline{2-2} 23 & 23 \\ \cline{2-2} & 1\end{array}\\ \\ \\

  • HCF of 510 : 2 × 3 × 5 × 17

  • HCF of 92 : 2 × 2 × 23

2 is common in both number's HCFs.

HCF = 2

Now,

LCM = 2 × 3 × 5 × 17 × 2 × 2 × 23

         ⇒  23,460‬.

LCM × HCF = 510 × 92

                  ⇒ 23460 × 2

                  ⇒ 49620

                  ⇒ 49620 = 49620

LCM and HCF is equals to product of two numbers.

Proved.

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