find the HCF and LCM of 90,144 by prime factorisation
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Answered by
24
prime factorisation of
90= 2*3*3*5
144=2*2*2*2*3*3.
2 and 3 are Common in both
HCF= 2 *3*3=18
LCM=2⁴ x 3²x 5 = 720
90= 2*3*3*5
144=2*2*2*2*3*3.
2 and 3 are Common in both
HCF= 2 *3*3=18
LCM=2⁴ x 3²x 5 = 720
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Answered by
43
here is your solution
Firstly factorise the (90,144)
90 = 2×3×3×5
144 = 2×2×2×2×3×3
For finding
LCM (90,144)= 2×2×2×2×3×3×5= 720
for finding
HCF(90,144)=2×3×3=18
I hope it helps you
Firstly factorise the (90,144)
90 = 2×3×3×5
144 = 2×2×2×2×3×3
For finding
LCM (90,144)= 2×2×2×2×3×3×5= 720
for finding
HCF(90,144)=2×3×3=18
I hope it helps you
thanks
:claps:
HCF( 90 , 144 ) = product of Smallest powers of each common prime factors of the numbers .
= 2¹ × 3² = 18
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