find the hcf and lcm of the following pairs of integers and verified that hcf multiplication lcm = products of the two no 1 96. and 104
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Answered by
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● HCF
104 = 96 × 1 + 8
96 = 8 × 12 + 0
So HCF = 8
● LCM
= 2 × 2 × 2 × 2 × 2 × 3 × 13 = 1248
■ Verification
LCM × HCF = Product of two nos.
8 × 1248 = 96 × 104
9984 = 9984
L.H.S = R.H.S
Hope it helps you.
104 = 96 × 1 + 8
96 = 8 × 12 + 0
So HCF = 8
● LCM
= 2 × 2 × 2 × 2 × 2 × 3 × 13 = 1248
■ Verification
LCM × HCF = Product of two nos.
8 × 1248 = 96 × 104
9984 = 9984
L.H.S = R.H.S
Hope it helps you.
Answered by
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the given numbers are
96 and 104
● HCF
104=96(1)+8
96= 8(12)+0
HCF is 8
●LCM
= 2×2×2×2×2×3×13 = 1248
●product of two numbers = LCM×HCF
104×96 = 1248×8
9,984 = 9,984
here is ur answer
i hope it helps u
O:D
96 and 104
● HCF
104=96(1)+8
96= 8(12)+0
HCF is 8
●LCM
= 2×2×2×2×2×3×13 = 1248
●product of two numbers = LCM×HCF
104×96 = 1248×8
9,984 = 9,984
here is ur answer
i hope it helps u
O:D
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