Question

Find the HCF by prime factorization method. a)658,940,1125 b) 762,1270​

Answer 1

a) H.C.F. of 658, 940, 1125 is 1.

b). H.C.F. of 762, 1270​ is 127.

Step-by-step explanation:

a). 658, 940, 1125

To find the H.C.F of 658, 940, 1125, we will prime factorize them.

658 = 1 * 2 * 7 * 49

940 =  1 * 2 * 2 * 5 * 47

1125 = 1* 3 * 3 * 5 * 5 * 5

Since there is no common factor execpt 1, 1 is the H.C.F. of 658, 940, 1125.

b). 762, 1270​

To find the H.C.F of 762, 1270, we will prime factorize them.

762 = 1* 2 * 3 * 127

1270 = 1 * 2 * 5 * 127

1, 2, and 127 are the common factors of 762, 1270. Since 127 is the largest, it is the H.C.F. of 762, 1270.

Learn more: Prime Factorization

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Answer 2

Answer:

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