Question

find the hcf of 116 290 580 by solution

Answer 1

Answer:

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Answer 2

Answer:

$\red { HCF(116,290,580)}\green { = 58}$

Step-by-step explanation:

$We\:have\\\:\:\:\: 116 = 2\times 2 \times 29 = 2^{2}\times 29^{1}\\290 = 2\times 5\times 29 = 2^{1}\times 5^{1}\times 29^{1}\\580 = 2\times 2\times 5 \times \times 29 = 2^{2}\times 5^{1}\times 29^{1}$

$HCF(116,290,580) = 2^{1} \times 29^{1} \\= 58$

Therefore.,

$\red { HCF(116,290,580)}\green { = 58}$

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