Find the HCF of 12156 and 37740 by euclid's algorithm
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euclids division lemma:
a=bq+r
37740=12156(3)+1272
12156=1272(9)+708
1272=708(1)+564
708=564(1)+264
564=264(2)+26
264=26(10)+4
26=4(6)+2
4=2(2)+0
HCF=2
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