find the HCF of 182, 252 ,324 by Euclid division algorithm
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aagnavaagna
Secondary SchoolMath 13+7 pts
Find hcf of 180, 252 & 324 by euclids division lemma
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Report by Tusharverma5498 10.10.2017
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saiTejasree11
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consider 252 and 324. here, a=324 and b=252
by euclid's division lemma-
a=bq+r, 0< or= r
324=252*1+72
252=72*3+36
72=36*2+0
therefore, HCF(252, 324)=36
Now consider 36 and 180. here a=180 and b=36.
by euclid's division lemma- a=bq+r, 0< or = r < b
180=36*5+0
therefore, HCF(180, 36)=36
Hence, HCF(180, 252, 324)=36
What is your question?
aagnavaagna
Secondary SchoolMath 13+7 pts
Find hcf of 180, 252 & 324 by euclids division lemma
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Report by Tusharverma5498 10.10.2017
Answers
saiTejasree11
SaiTejasree11 Expert
consider 252 and 324. here, a=324 and b=252
by euclid's division lemma-
a=bq+r, 0< or= r
324=252*1+72
252=72*3+36
72=36*2+0
therefore, HCF(252, 324)=36
Now consider 36 and 180. here a=180 and b=36.
by euclid's division lemma- a=bq+r, 0< or = r < b
180=36*5+0
therefore, HCF(180, 36)=36
Hence, HCF(180, 252, 324)=36
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