Math, asked by mananbalar1502, 7 months ago

Find the HCF of (2^3×3^2×5), (2^2×3^3×5^2) and (2^4×3×5^3×7)

Answers

Answered by sonai25
0

Answer:

2^2×3×5=60

Step-by-step explanation:

the common powers among three digits is taken as HCF

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Answered by shanjayram
3

Answer:

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