Question

find the hcf of 2^3*3^2*5*7^4,2^2*3^5*5^2*7^3,2^3*5^3*7^2​

Answer 1

Answer:

980

Step-by-step explanation:

Let the 3 numbers be x, y & z.

x=2³*3²*5*7⁴

y=2²*3⁵*5²*7³

z=2³*5³*7²

We know, HCF is the product of common factors with their least powers.

HCF(x,y,z)=2²*5*7²

or  HCF(x,y,z)=4*49*5

or HCF(x,y,z)=980

Answer 2

Let us consider the numbers are :-

A=2³*3²*5*7⁴

B=2²*3⁵*5²*7³

C=2³*5³*7²

HCF is the product of common factors with their least powers.

∴ HCF :-

(A, B, C)=2²*5*7²

=4 ×5 ×49

=$980$

Ans :- HCF of three numbers will be 980.