find the HCF of 2160 and 847 using Euclid's division algorithm
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Answer:
Step-by-step explanation:
a=2160,b=847
By Euclid's lemma
a=bq+r, 0≤r<b
2160=847×2+466
847=466×1+381
466=381×1+85
381=85×4+41
85=41×2+3
41=3×13+2
3=2×1+1
2=1×2+0
as 1 is the HCF of 847 and 2160
∴ 847 and 2160 are co-primes as they have only 1 as their HCF.
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