find the HCF of 24,60 ,48 and108
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Answer:
HCF of 24 , 60 , 48 , 108 is 12
Step-by-step explanation:
24 = 2 x 2 x 2 x 3 = 2³ x 3¹
60 = 2 x 2 x 3 x 5 = 2² x 3¹ x 5¹
48 = 2 x 2 x 2 x 2 x 3 = 2⁴ x 3¹
108 = 2 x 2 x 3 x 3 x 3 = 2² x 3³
we know that HCF of the numbers is equal to product of lowest powers of the common factors in the numbers
common factors in the numbers 24, 60 , 48 , 108 are 2 , 3
lowest power of 2 is 2²
lowest power of 3 is 3¹
so HCF of 24 , 60 , 48 , 108 = 2² x 3¹ = 4 x 3 = 12
Therefore HCF of 24 , 60 , 48 , 108 is 12
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