Find the HCF of 24 abc3, 36ab3c , and 48a3bc
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To find the HCF find all the factors of the given data:
24 abc³ =12abc*2c²
36ab³c=12abc*3b²
48a³bc=12abc*4a²
Hence we see that 12abc is common in all the data.
So the HCF is 12abc.
Hope it helps.
Answered by
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Here, 24abc^3=2^3×3×abc^3
36ab^3c=2^2×3^2×ab^3c
48a^3bc=2^4×3×a^3bc
Now their HCF=2^2×3 abc=12abc
36ab^3c=2^2×3^2×ab^3c
48a^3bc=2^4×3×a^3bc
Now their HCF=2^2×3 abc=12abc
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