find the HCF of 250 and 400 by division method with process
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Using Euclid’s division algorithm, find the HCF of
250, 175 and 425
Answer :
Given numbers are 250, 175 and 425
∴ 425 > 250 > 175
On applying Euclid’s division lemma for 425 and 250, we get
425 = 250 × 1 + 175
Here, r = 175 ≠ 0.
So, again applying Euclid’s division lemma with new dividend 250 and new divisor 175, we get
250 = 175 × 1 + 75
Here, r = 75 ≠ 0
So, on taking 175 as dividend and 75 as the divisor and again we apply Euclid’s division lemma, we get
175 = 75 × 2 + 25
Here, r = 25 ≠ 0.
So, again applying Euclid’s division lemma with new dividend 75 and new divisor 25, we get
75 = 25 × 3 + 0
Here, r = 0 and divisor is 25.
So, HCF of 425 and 225 is 25.
Now, applying Euclid’s division lemma for 175 and 25, we get
175 = 25 × 7 + 0
Here, remainder = 0
So, HCF of 250, 175 and 425 is 25.
250, 175 and 425
Answer :
Given numbers are 250, 175 and 425
∴ 425 > 250 > 175
On applying Euclid’s division lemma for 425 and 250, we get
425 = 250 × 1 + 175
Here, r = 175 ≠ 0.
So, again applying Euclid’s division lemma with new dividend 250 and new divisor 175, we get
250 = 175 × 1 + 75
Here, r = 75 ≠ 0
So, on taking 175 as dividend and 75 as the divisor and again we apply Euclid’s division lemma, we get
175 = 75 × 2 + 25
Here, r = 25 ≠ 0.
So, again applying Euclid’s division lemma with new dividend 75 and new divisor 25, we get
75 = 25 × 3 + 0
Here, r = 0 and divisor is 25.
So, HCF of 425 and 225 is 25.
Now, applying Euclid’s division lemma for 175 and 25, we get
175 = 25 × 7 + 0
Here, remainder = 0
So, HCF of 250, 175 and 425 is 25.
anshika321:
read the question properly
Answered by
4
250 < 400
400 = 250 x 1 + 150
250 = 150 x 1 + 100
150 = 100 x 1 + 50
100 = 50 x 2 +0
here the remainder is 0.
therefore, HCF = 50
hope it helps.........
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