find the HCF of 255 ,1309 and 1326 by Euclid division lemma .
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we have dividend=255and divisor =1309
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1st, we shall find the HCF of 255 and 1309.
1309 > 255
(1) 1309 = 255 * 5 + 34
Here remainder is not equal to 0. Therefore, We apply division to 255 and 34.
(2) 255 = 34 * 7 + 17
Here remainder is not equal to 0. Therefore, we apply division to 34 and 17.
(3) 34 = 17 * 2 + 0
Here remainder is 0.
Therefore the HCF of 255 and 1309 = 17.
Now,
Find the HCF of 17 and 1326.
1326 > 17
= > 1326 = 17 * 78 + 0.
Here remainder is not equal to 0.
Therefore the HCF of 255,1309,1326 is 17.
Hope this helps!
1309 > 255
(1) 1309 = 255 * 5 + 34
Here remainder is not equal to 0. Therefore, We apply division to 255 and 34.
(2) 255 = 34 * 7 + 17
Here remainder is not equal to 0. Therefore, we apply division to 34 and 17.
(3) 34 = 17 * 2 + 0
Here remainder is 0.
Therefore the HCF of 255 and 1309 = 17.
Now,
Find the HCF of 17 and 1326.
1326 > 17
= > 1326 = 17 * 78 + 0.
Here remainder is not equal to 0.
Therefore the HCF of 255,1309,1326 is 17.
Hope this helps!
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