Question

find the smallest number which when divided by 4 12 16 and 20 leaves no remainder no remainder

Answer 1

[ first of all we need to find the LCM of all the given numbers ]

LCM of 4, 12, 16 & 20
= 2×2×2×2×3×5
= 2⁴×3×5
= 240

240 is the smallest number which when divided by all the given numbers leaves no remainder


$hope \: this \: answer \: helps \: you \\ \\ thankyou$

Answer 2

Step-by-step explanation:

finding the lcm of these numbers is the answer of the given question

lcm equals 240

answer equals 240