Find the hcf of 312 and 27 using Euclids division algorithm. Find lcm and verify Lcm × hcf= product of the two numbers
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Using euclids
312=27*11+15
27=15*1+12
15=12*1+3
12=3*4+0
So 3is the required no. I. E hcf... Of 312 and 27
312=27*11+15
27=15*1+12
15=12*1+3
12=3*4+0
So 3is the required no. I. E hcf... Of 312 and 27
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