Math, asked by kumarisunitalkr, 9 months ago

fIND THE HCF OF 321 AND 396 USING EUCLID,S DIVISION ALOGRITHM

Answers

Answered by svptarun

2

396=321×1+75

321=75×4+21

75=21×3+12

21=12×1+9

12=9×1+3

9=3×3+0

HCF(396,321)=3

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