find the HCF OF 441,567,693 by using euclid division alogrithm
Answers
Answered by
32
Hi friend, Harish here.
Here is your answer:
By Euclid's Division Lemma,
a = b q + r : 0 ≤ r < b.
Then, HCF of 441 , 567 , 693 are:
⇒ 693 = 567 × 1 + 126
⇒ 567 = 126 × 4 + 63.
⇒ 126 = 63 × 2 + 0.
Now, HCF of 693, & 567 is 63.
Then to find HCF of all three number , We must find HCF of (63 & 441)
⇒ 441 = 63 × 7 + 0.
Therefore 63 is the HCF of all three number.
_______________________________________________
Hope my answer is helpful to you
Here is your answer:
By Euclid's Division Lemma,
a = b q + r : 0 ≤ r < b.
Then, HCF of 441 , 567 , 693 are:
⇒ 693 = 567 × 1 + 126
⇒ 567 = 126 × 4 + 63.
⇒ 126 = 63 × 2 + 0.
Now, HCF of 693, & 567 is 63.
Then to find HCF of all three number , We must find HCF of (63 & 441)
⇒ 441 = 63 × 7 + 0.
Therefore 63 is the HCF of all three number.
_______________________________________________
Hope my answer is helpful to you
Similar questions