Find the HCF of 456 and 256 by Euclid's division lemma
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Answered by
2
according to Euclid division lemma ,
a = bq + r
now,
step for finding HCF of 456 and 256
===============================
use a = bq + r for 456 and 256
456 = 256 ×1 + 200
remainder 200 so,
again use Euclid lemma for 256 and 200
256 = 200× 1 + 56
remainder 56 so,
agian use Euclid lemma for 200 and 56
200 = 3 × 56 + 32
remainder 32 so,
again E. D lemma , for 56 and 32
56 = 1 × 32 + 24
again E.D lemma for 32 and 24
32 = 1× 24 + 8
again E.D lemma for 24 and 8
24 = 8 ×3 + 0
here remainder zero so,
HCF of 456 and 256 = 8
a = bq + r
now,
step for finding HCF of 456 and 256
===============================
use a = bq + r for 456 and 256
456 = 256 ×1 + 200
remainder 200 so,
again use Euclid lemma for 256 and 200
256 = 200× 1 + 56
remainder 56 so,
agian use Euclid lemma for 200 and 56
200 = 3 × 56 + 32
remainder 32 so,
again E. D lemma , for 56 and 32
56 = 1 × 32 + 24
again E.D lemma for 32 and 24
32 = 1× 24 + 8
again E.D lemma for 24 and 8
24 = 8 ×3 + 0
here remainder zero so,
HCF of 456 and 256 = 8
Anonymous:
Thanks a lot abhi !!
Answered by
1
456=256(1)+200
256=200(1)+56
200=56(3)+32
56=32(1)+24
32=24(1)+8
24=8(3)+0
hcf=8
256=200(1)+56
200=56(3)+32
56=32(1)+24
32=24(1)+8
24=8(3)+0
hcf=8
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