Math, asked by chutkiaki001, 1 year ago

without using table, evaluate 3 cos 80° cosec 10 °+2 sin 59 °degree sec 31 °

Answers

Answered by Anonymous
83
using trigonometric formula for complementary angles

we can solve..


see attachment

hope it will help u
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Answered by pinquancaro
42

Answer:

3\cos 80^\circ\csc 10^\circ+2\sin 59^\circ\sec 31^\circ=5

Step-by-step explanation:

Given : Expression 3\cos 80^\circ\csc 10^\circ+2\sin 59^\circ\sec 31^\circ

To find : Evaluate the expression ?

Solution :

Expression 3\cos 80^\circ\csc 10^\circ+2\sin 59^\circ\sec 31^\circ

Re-write using trigonometry properties,

=3\cos (90-10)^\circ\frac{1}{\sin 10^\circ}+2\sin (90-31)^\circ\frac{1}{\cos 31^\circ}

=3\sin 10^\circ\times \frac{1}{\sin 10^\circ}+2\cos 31^\circ\times \frac{1}{\cos 31^\circ}

=3(1)+2(1)

=5

Therefore, 3\cos 80^\circ\csc 10^\circ+2\sin 59^\circ\sec 31^\circ=5

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