find the HCF of 510 and 92 by euclids division algorithm
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Answered by
13
92) 510 (5
-460
-------
50) 92 (1
-50
------
42) 50 (1
-42
-----
8) 42 (5
-40
------
2) 8 (4
8
----
a = bq + r
510 = 92 × 5 + 50
92 = 50 × 1 + 42
50 = 42 ×1 + 8
42 = 8 × 5 + 2
8 = 2 × 4 + 0
here at last 2 is divisor.
So, HCF = 2...
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Answer:
hpe it helps you :)
Step-by-step explanation:
the answer is correct so the HCF is 2
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