Find the HCF of 52 and 117 and express it in the form 52x+117y
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HCF of 52 and 117 is 13
so we can write it in the form of
52×1/13+117×1/13
so we can write it in the form of
52×1/13+117×1/13
hadi88923p2ec6c:
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what you do in last
I have put x equals to 1 upon 13 and Y is equals to 1 upon 13 so that the sum becomes 13
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