Question

Find the Hcf of 52and 117 and express it in the form of 52x+117y

Answer 1

#Hello friend
______________________________________

Hcf of 52 and 117

117=52*2+13

52=13*4+0

So the hcf will be 13

13=52x+117y

x=1/13

y=1/13
____________________________________

Hope it helps!