Question

Find the HCF of 57 and 117 and Express it in the form 57x+117y

Answer 1

Answer:

52x + 117y i.e. as 52 (-2) + 117 (1)

Step-by-step explanation:

Solution:-

By Euclid's Division Lemma 117 > 52

117 = (52 × 2) + 13 (52 is the divisor)

52 = 13 × 4 + 0 ; The division process ends here, as remainder is 0. So, HCF is 13 (Here, 13 is divisor)

13 can also be expressed as 52x + 117y i.e. as 52 (-2) + 117 (1)

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