Question

find the hcf of 60 and 105 by repeated division method.​

Answer 1

Step-by-step explanation:

60 − 1=59

60 − 1=5959 - 3 =56

60 − 1=5959 - 3 =5656 - 5 =51

60 − 1=5959 - 3 =5656 - 5 =5151 - 7 =44

60 − 1=5959 - 3 =5656 - 5 =5151 - 7 =4444 - 9 =35

60 − 1=5959 - 3 =5656 - 5 =5151 - 7 =4444 - 9 =3535 - 11 = 24

60 − 1=5959 - 3 =5656 - 5 =5151 - 7 =4444 - 9 =3535 - 11 = 2424 - 13 = 11

60 − 1=5959 - 3 =5656 - 5 =5151 - 7 =4444 - 9 =3535 - 11 = 2424 - 13 = 1111 - 15 = -4

60 − 1=5959 - 3 =5656 - 5 =5151 - 7 =4444 - 9 =3535 - 11 = 2424 - 13 = 1111 - 15 = -4hope it helps u.⫷⫷

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