Question

find the HCF of 65 and 117 and Express it in the form 65 M + 117 n​

Answer 1

Step-by-step explanation:

it will be 3

65 and 117 =5*13*3*3

Answer 2

Answer:

65×2+117×1

m=2

n=1

Step-by-step explanation:

According to lemma:-

a=bq+r here, 0<or equals tor<b

117=65×1+52

65=52×1+13

52=13×4+0

So hcf is 13

See the results when remainder 13

Now

13=65-52×1

13=65-(117-65×1)1

13=65-(117+65×1)1

13=65×2+117×1

m=2

n=1

65×2+117×1