Question

find the HCF of 6ra^2x^2y^2z,15r^3xy^3z^4,36ab^2x^4y^3,12xyz​

Answer 1

Answer:

3xyz

Step-by-step explanation:

6ra²x²y²z=2*3ra²x²y²z

15r³xy³z4=3*5r³xy³z^4

36ab²x^4y³=2^2*3^2ab²x^4y³

12xyz=2*2*3*xyz

We observe the common numbers are 3

for r= 0 power

a: 0 power

x:  power 1

y: power 1

z: power 1

Hence HCF= 3*r^0 * a^0*x*y*z

=3xyz