Question

find the hcf of 805 and 915 by Euclid division lemma and also express in form of linear combination​

Answer 1

Answer:

Step-by-step explanation:

915=805×1+110

805=110×7+35

110=35×3+5

35=5×7+0

answer is 5 because its is the smallest number which is repeated twice so

hcf=5

Answer 2

Answer:

Step-by-step explanation: We know,

According to Euclid's division lemma

a= bq +r

Here, 915 > 805

Therefore,

915= 805(1) + 110

805=110(7) + 35

110= 35(3) + 5

35= 5(7) + 0

Therefore, the HCF(805,915) = 5

I HOPE IT WILL HELP U :D

THANKS

PLEASE MARK ME BRAINLIEST