Question

Find the hcf of 808,568,1112 by long division

Answer 1

Hii..
Here is your answer

Solution:-
LCM of:-
$808 = 2 \times 2 \times 2 \times 101 \\ 568 = 2 \times 2 \times 2 \times 71 \\ 1112 = 2 \times 2 \times 2 \times 139$
$= > 2 \times 2 \times 2 \\ = > 8$
HCF of 808,568 and 1112 is 8.

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Answer 2

568)808(1

_568

240)568(2

-480

88)240(2

-176

64)88(1

-64

24)64(2

-48

16)24(1

-16

8)16(2

-16

xx

8)1112(139

-8

31

-24

72

-72

xx

H.c.f=8

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