Question

find the HCF of 81 and 237 and represent it in the form of 81x+237y find the value of x and y​

Answer 1

Answer:

By Euclid s division lemma we will find hcf and then equvate to 81x+237y.

Step-by-step explanation:

hcf of 237 and 237= 81*2+75

81=75*1+6

75=6*12+3

6=3*2

There fore hcf is 3.

Now,

3=81x+237y

81x+237y-3=0

3(27x+79y-1)=0

x=1-79y

27

by susbsituting this, we get,

27*1-79y +79y-1=0

27

1-79y+79y-1

=0.

And therefore, hence, 81x+237y can t be found out.

OR

The equation of 81x+237y might be wrong!!

OR

it can be 81x-237y, and if it is so, then, your answer of finding x and y is as follows,

countinuation,

instead of 27x+79y-1=0, it is,

27x-79y-1=0

x= 1+79y

27

by subsituting this, we get,

27*1+79y +79y-1=0

27

1+79y+79y-1=0

158y=0

y= 1 .

158

And hence,

x= 1+79*1/158

27

= 1+1/2

27

= 2+1

2

27

= 3 * 1

2 27

= 1

18.

And hence follow and like and mark the brainliast answer please!!