Math, asked by keshavprajapati4408, 1 year ago

Find the HCF of 91,112,49 by short process

Answers

Answered by abhi178
66
HCF { 91, 112, 49} = Highest common factor of { 91, 112, 49}
so, factorise
factor of 91 = 13 × 7
factor of 112 = 7 × 3 × 2
factor of 49 = 7 × 7

Highest common factor = 7
so, HCF {91, 112, 49 } = 7
Answered by Anonymous
39
We can find the HCF by prime factorization method :-

Prime factorization of 91 = 13 × 7 
Prime factorization of 112 = 7 × 3 × 2 
Prime factorization of 49 = 7 × 7 

7 is common in  the prime factorization of all the numbers.

Hence ,
HCF = 7
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