Math, asked by praveen1969, 1 year ago

find the HCF of 96,528,1584,2016​

Answers

Answered by Anonymous
6

Let us find out the HCF of 96, 528, 1584, 2016 through prime factorisation method.

✴ Prime factors of 96 = 2 × 2 × 2 × 2 × 2 × 3

✴ Prime factors of 528 = 2 × 2 × 2 × 2 × 3 × 11

✴ Prime factorisation of 1584 = 2 × 2 × 2 × 2 × 3 × 3 × 11

✴ Prime factorisation of 2016 = 2 × 2 × 2 × 2 × 2 × 3 × 3 × 7

➡ Common Factors of 96, 528, 1584, 2016 = 2 × 2 × 2 × 2 × 3 = 48

Thus, HCF of 96, 528, 1584, 2016 is 48.

Answered by Anonymous
7

96 = 2 \times 2 \times 2 \times 2 \times 2 \times 3

528 = 2 \times 2 \times 2 \times 2 \times 3 \times 11

1584 = 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 11

2016 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times  \times 7

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96 =   {2}^{5}  \times  {3}^{1}

528 =  {2}^{4}  \times  {3}^{1}  \times  {11}^{1}

1584 =  {2}^{4}  \times  {3}^{2}  \times  {11}^{1}

2016 =  {2}^{5}  \times  {3}^{2} \times  {7}^{1}

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So HCF=

 {2}^{4}  \times  {3}^{1}

2 \times 2 \times 2 \times 2  \times 3

 = 48

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