find the hcf of no 72 & 96 by euclid division algorithm and express it in the form 96m+72n where m and n are some integers.
Answers
Answered by
138
Hi ,
___________________________
Euclid's Division Lemma :
Given positive integers a and b ,
there exists unique integers q and r
satisfying
a = bq + r ,
Where 0 less than or equal to r
___________________________
Applying Euclid's Division algorithm
to 72 and 96 , we get
96 = 72 × 1 + 24 ----( 1 )
72 = 24 × 3 + 0 -----( 2 )
Therefore 24 is the HCF of 72 and 96
From ( 1 ),
24 = 96 - 72 × 1
= 96 ( 1 ) + 72 × ( - 1 )
It is in the form of
= 96m + 72n
I hope this helps you.
***
___________________________
Euclid's Division Lemma :
Given positive integers a and b ,
there exists unique integers q and r
satisfying
a = bq + r ,
Where 0 less than or equal to r
___________________________
Applying Euclid's Division algorithm
to 72 and 96 , we get
96 = 72 × 1 + 24 ----( 1 )
72 = 24 × 3 + 0 -----( 2 )
Therefore 24 is the HCF of 72 and 96
From ( 1 ),
24 = 96 - 72 × 1
= 96 ( 1 ) + 72 × ( - 1 )
It is in the form of
= 96m + 72n
I hope this helps you.
***
Answered by
24
HCF (96 & 72) = 96 = 72 *1 + 24
72 = 24 * 3 + 0
therefore HCF is 24...
72 = 24 * 3 + 0
therefore HCF is 24...
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