find the hcf of number 72 and 96 by euclid division algorithm and express it in the form 96m+72n where m and n are integer
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96=72*1+24
72=24*3+0
HCF=24(last divisor)
96m+72n=24
24(4m+3n)=24
4m+3n=1
By trial and error method,
m=1. n= -1
Hope it helps u and make it as brainliest!
72=24*3+0
HCF=24(last divisor)
96m+72n=24
24(4m+3n)=24
4m+3n=1
By trial and error method,
m=1. n= -1
Hope it helps u and make it as brainliest!
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