find the hcf of polynomial x cube -1 and x square -1
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Solution :
Resolving the factors of ( x³ - 1 ) and
( x² - 1 ),
x³ - 1³ = ( x - 1 )( x² + x + 1 )
x² - 1² = ( x - 1 )( x + 1 )
Now ,
HCF = ( x - 1 )
••••
Resolving the factors of ( x³ - 1 ) and
( x² - 1 ),
x³ - 1³ = ( x - 1 )( x² + x + 1 )
x² - 1² = ( x - 1 )( x + 1 )
Now ,
HCF = ( x - 1 )
••••
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