Find the hcf of the 1128 and 1464 by using uclids division lamma?
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Answer:
1128 ) 1464 ( 1
1128
336
1464 = 1128 × 1 + 336
336 ) 1128 (3
1008
120
1128 = 336 × 3 + 120
120 ) 336 ( 2
240
96
336 = 120 × 2 + 96
96 ) 120 ( 1
96
24
120 = 96 ×1 + 24
24 ) 96 ( 4
96
0
96 = 24 × 4 + 0
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