Question

Find the initial velocity of a car which is stopped in 10 seconds by applying brakes the retardation due to breaks in 2.5ns^2

Answer 1

Answer:

25nm/s

Explanation:

v= 0m/s , t=10s , a= 2.5nm/s^2 then by using the equations of motion v=u+at we obtain that initial velocity is 25nm/s

Answer 2

Explanation:

Answer ⤵️

Initial velocity, u=?

Final velocity, v=0m/s (car is stopped)

Acceleration, a=−2.5m/s²(negative because it is retardation)

Time, t=10s

Use the relation of the first equation of motion:

v=u+at

0=u+(−2.5)×10

u=25m/s

xXitzSweetMelodyXx