Find the HCF of the following:
a.136,170 and 255
b.36, 42 and 45
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HCF of 136, 170, and 255 is 17
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HCF of 36 and 42 is 6
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Answer: The prime factorization of 45 is 5 x 3 x 3. The prime factorization of 60 is 2 x 2 x 3 x 5. Therefore the HCF (highest common factor) of these two numbers is the set of factors that appear in both: that's one 3 and one 5.
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