find the hcf of the following by prime factorisation and by continued division method
(i) 48, 64
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48=2x2x2x2x3
64=2x2x2x2x2x2
Hcf=2^4
=16
Continued division
48,64. 2
24,32. 2
12,16. 2
6,8. 2
3,4. 2
3,2. 2
3,1. 3
1,1. 1
2x2x2x2x2x2x2x3
2x8
16
64=2x2x2x2x2x2
Hcf=2^4
=16
Continued division
48,64. 2
24,32. 2
12,16. 2
6,8. 2
3,4. 2
3,2. 2
3,1. 3
1,1. 1
2x2x2x2x2x2x2x3
2x8
16
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