Question

find the hcf of the following by prime factorisation and by continued division method


(i) 48, 64​

Answer 1

Answer:

see the images

Step-by-step explanation:

Answer 2

48=2x2x2x2x3
64=2x2x2x2x2x2
Hcf=2^4
=16
Continued division
48,64. 2
24,32. 2
12,16. 2
6,8. 2
3,4. 2
3,2. 2
3,1. 3
1,1. 1


2x2x2x2x2x2x2x3
2x8
16