Question

find the HCF of the following by prime factorization 45 and 90

Answer 1

Prime factorisation of 45 = 3,3,5
Prime factorisation of 90= 2,3,3,5
Multiply of no common in both= 3×3×5=45
So HCF= 45

Answer 2

$\huge \mathfrak{heya \: mate}$

$\huge\mathbb{HERE'S YOUR ANSWER}$

45 = 3 × 3 × 5
90 = 2 × 3 × 3 × 5

therefore,HCF = 3 × 3
=9

$\bold{explanation}$
As we all know that HCF means highest common factor so we have to choose the common factors from the given numbers...
i.e ., here 45 and 90 has 3 and 3 as their common factors..
so,HCF = 3 × 3
=9