Question

Find the HCF of the following by the given method. a)9, 72 and 21 by listing factors b)22, 77 and 121 by prime factorostriston c)9, 18 and 27 by long division method d)44, 56 and 68 by division by common factor method


who will Answer I will mark as Brainliest ​

Answer 1

Answer:

Tell a teacher

- _ -

Step-by-step explanation:

Answer 2

Answer:

I have sent you the answer sister

Step-by-step explanation:

Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800