FIND THE HCF OF THE FOLLOWING IN LONG DIVVISION METHOD:-A)216,124 B)60,84 C)51,93 D)124,224 E)119,136 F)256,78
Answers
Answer:
Q1) Find the HCF of the following numbers :
(i) 18, 48 (ii) 30, 42 (iii) 18, 60 (iv) 27, 63
(v) 36, 84 (vi) 34, 102 (vii) 70, 105, 175
(viii) 91, 112, 49 (ix) 18, 54, 81 (x) 12, 45, 75
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SOLUTION:
i) 18,48
18=2\times3\times3
48=2\times2\times2\times2\times3
The common factor of 18 and 48 are 2,3. thus, HCF of 18 and 48 is2\times3=6
ii) 30,42
30=2\times3\times5
42=2\times3\times7
The common factor of 30 and 42 are 2 and 3
thus, HCF of 30,42 are 2\times3=6
iii) 18,60
18=2\times3\times3
60=2\times2\times3\times5
The common factor of 18 and 60 are 2,3. thus, HCF of 18 and 60 are 2\times3=6
iv) 27, 63
27=3\times3\times363=3\times3\times7
The common factor for 27 and 63 is 3
thus, HCF of 27 and 63 is 3\times3=9
v) 36,84
36=2\times2\times3\times384=2\times2\times3\times7
The common factor of 36 and 84 is 2\times3
thus, HCF of 36 and 84 is 2\times2\times3=12
vi) 34, 102
34=2\times17102=2\times3\times17
The common factor in 34 and 102 is 2, 17.
thus, HCF for 34 and 102 is 2\times17=34
vi) 70, 105, 175
70=2\times5\times7
105=3\times5\times7
175=5\times5\times7
The common factor in 70, 105 and 175 are 5, 7.
thus, HCF for 70,105 and 175 is 5\times7=35
vii) 91,112,49
91=7\times13112=2\times2\times2\times2\times749=7\times7
The common factors of 91, 112, and 49 are 7.
therefore, HCF of 91, 112 and 49 are 7.
viii) 18, 54,81
18=2\times3\times354=2\times3\times3\times381=3\times3\times3\times3
therefore common factors between 18, 54, 81 is 3X3=9
xi) 12,45,75
therefore, the coomon factor is 3.
HCF of 12,45,75 is 3.
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